Page 85. In the definition of Gamble 1 exchange min for max.
Page 104. Equation (i). Exchange Ford for Jaguar and Jaguar for Ford.
Page 105. Last line. The utility of the Saab should be 0.55 + 0.36 = 0.91.
Page 115. Solution to 5.6. Line 2 should read “…x ≻ y implies that x ≻ z or z ≻ y. The second possibility, z ≻ y, is inconsistent with what we initially supposed”. In the solution to 5.7 all that can be concluded is that 0.9B + 0.1C = 0.6B + 0.4D.
Page 128. Second paragraph line 9. Exchange biased for not biased.
Page 132. In the solution to exercise 6.6, part (a), delete 1/6 · 1/6 (the answer, 6/36, is still correct). The solution to problem 6.7 should be 10/37 ≈ 0.27. In the solution to exercise 6.8 exchange 0.53 for 0.552.
Page 157. In line 8, exchange p(x) > 0 for p(x) < 0 and in line 18, p(x ∨ ¬x) > 1 for p(x ∨ ¬x) < 1. In the last paragraph line 4 the last x' should be in italic typeface and in line 5, exchange y for x'.
Page 168. Proof of Theorem 8.1. The third line, should read ”between x and y at…”.
Page 168. Main text, line 1. Exchange regard x and y for regard x and z.
Page 168. Main text, line 2. Exchange y health for z health.
Page 179. Line 5. Exchange xpy for xpz.
Page 186. In line 2, x-3/2 divided by x-1/2 should be x-1, not x-3. In line 4, x-5/3 divided by x-2/3 should be x-1, not x-10/3.
Page 189. The expected utility for taking boxes 1 and 2 is $11,000, not $10,000 (because u($0) should be u($1000)).
Page 194. Second paragraph. Exchange all X for Y and all Y for X.
Page 262. Solution to 12.8. (R2, C1) is also a Nash equilibrium.
Page 267. Lines 2–3. Exchange O were to prefer f to e for Q were to prefer b to a.
Page 282. Exercise 13.1 line 2. Delete or f.
Page 284. Exercise 13.5(b). The answer is correct, but No should be deleted.
Page 286. Line 12. C and D have been reversed in the definition of the lotteries.
Page 308. Entry Herodotus (1954). Exchange Penquin for Penguin.